Solving Proportions Finding M In 20/m = 15/9

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Understanding Proportions

In the realm of mathematics, a proportion is a statement that two ratios or fractions are equal. Proportions are a fundamental concept with wide-ranging applications, from scaling recipes in the kitchen to calculating distances on a map. Understanding how to solve proportions is a crucial skill in algebra and beyond. In this article, we will delve into the process of solving for an unknown variable in a proportion, specifically focusing on the equation 20m=159\frac{20}{m} = \frac{15}{9}. We will explore the underlying principles, the step-by-step method, and the reasoning behind each step, ensuring a clear and comprehensive understanding for anyone looking to master this essential mathematical technique. This comprehensive exploration will provide you with a solid foundation for tackling various proportion problems and applying this knowledge in real-world scenarios. By the end of this discussion, you will be equipped with the skills and confidence to solve similar proportion problems with ease. The principles discussed here extend beyond this specific example and are applicable to a wide range of proportion-related challenges.

Setting up the Proportion

To begin, let's clarify the given proportion: 20m=159\frac{20}{m} = \frac{15}{9}. This equation states that the ratio of 20 to mm is equivalent to the ratio of 15 to 9. Our goal is to find the value of mm that makes this statement true. The variable mm represents an unknown quantity, and solving the proportion involves isolating mm on one side of the equation. This process requires a systematic approach, leveraging the properties of proportions and algebraic manipulation. Recognizing the structure of the proportion is the first step in devising a solution strategy. We have two fractions set equal to each other, and our task is to determine the value of the denominator in the first fraction. The relationship between the numerators and denominators in both fractions holds the key to finding the solution. Understanding this relationship is crucial for successfully solving the proportion and ensuring that the equality holds true. With a clear understanding of the goal and the given information, we can proceed to the next step, which involves applying a fundamental property of proportions to simplify the equation.

Cross-Multiplication: A Key Technique

A powerful technique for solving proportions is cross-multiplication. This method stems from the fundamental property that if two fractions are equal, then their cross-products are also equal. In other words, for the proportion ab=cd\frac{a}{b} = \frac{c}{d}, we can say that aimesd=bimesca imes d = b imes c. Applying this to our proportion, 20m=159\frac{20}{m} = \frac{15}{9}, we multiply 20 by 9 and mm by 15, resulting in the equation 20imes9=15imesm20 imes 9 = 15 imes m. This step transforms the proportion into a simpler linear equation, making it easier to isolate the variable mm. Cross-multiplication is a shortcut that combines the steps of multiplying both sides of the equation by the denominators, thereby eliminating the fractions. It is a widely used and efficient technique for solving proportions, especially when dealing with more complex equations. The validity of cross-multiplication rests on the properties of equality and the manipulation of fractions. Understanding the underlying principle behind this technique provides a deeper understanding of the solution process. Now that we have applied cross-multiplication, we have a linear equation that we can solve using standard algebraic methods. The next step involves simplifying the equation and isolating mm to determine its value.

Simplifying the Equation

After cross-multiplying, we have the equation 20imes9=15imesm20 imes 9 = 15 imes m. Let's simplify this equation by performing the multiplication on the left side: 20imes9=18020 imes 9 = 180. So, our equation becomes 180=15m180 = 15m. Now, to isolate mm, we need to divide both sides of the equation by 15. This is a fundamental algebraic operation that maintains the equality of the equation while bringing us closer to the solution. Dividing both sides by the same non-zero number is a crucial step in solving for a variable. In this case, dividing by 15 will effectively undo the multiplication of mm by 15, leaving mm isolated on one side of the equation. This process is based on the inverse relationship between multiplication and division. Simplifying equations is a core skill in algebra, and it often involves combining like terms, performing arithmetic operations, and applying the properties of equality. In this instance, simplification has led us to a straightforward equation that can be easily solved for mm. The next step is to perform the division and find the numerical value of mm. This will give us the solution to the original proportion.

Isolating mm and Finding the Solution

To isolate mm in the equation 180=15m180 = 15m, we divide both sides by 15: 18015=15m15\frac{180}{15} = \frac{15m}{15}. This simplifies to 12=m12 = m. Therefore, the value of mm that satisfies the proportion 20m=159\frac{20}{m} = \frac{15}{9} is 12. This means that the ratio of 20 to 12 is equivalent to the ratio of 15 to 9. Isolating the variable is a fundamental technique in algebra, and it often involves using inverse operations to undo the operations performed on the variable. In this case, we used division to undo the multiplication. The solution m=12m = 12 represents the specific value that makes the two ratios in the proportion equal. Finding this value is the ultimate goal of solving the proportion. Now that we have found the solution, it is always a good practice to check our answer to ensure that it is correct. This involves substituting the value of mm back into the original proportion and verifying that the equality holds. This step helps to catch any potential errors and provides confidence in the solution.

Verifying the Solution

To verify our solution, we substitute m=12m = 12 back into the original proportion: 2012=159\frac{20}{12} = \frac{15}{9}. Now, we simplify both fractions to see if they are equal. The fraction 2012\frac{20}{12} can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 4. This gives us 20÷412÷4=53\frac{20 \div 4}{12 \div 4} = \frac{5}{3}. Similarly, the fraction 159\frac{15}{9} can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 3. This gives us 15÷39÷3=53\frac{15 \div 3}{9 \div 3} = \frac{5}{3}. Since both fractions simplify to 53\frac{5}{3}, we have verified that 2012=159\frac{20}{12} = \frac{15}{9}. This confirms that our solution, m=12m = 12, is correct. Verification is an important step in problem-solving, as it helps to ensure the accuracy of the solution. It provides a check that the value we found satisfies the original equation or condition. In the context of proportions, verification involves substituting the value back into the proportion and confirming that the two ratios are indeed equal. This process reinforces our understanding of the problem and the solution. With the solution verified, we can confidently state that m=12m = 12 is the correct answer.

Conclusion

In summary, we have successfully solved for mm in the proportion 20m=159\frac{20}{m} = \frac{15}{9}. We began by understanding the concept of proportions and recognizing that we needed to find the value of mm that makes the two ratios equal. We then applied the technique of cross-multiplication to transform the proportion into a simpler equation. After simplifying the equation and isolating mm, we found that m=12m = 12. Finally, we verified our solution by substituting it back into the original proportion and confirming that the equality holds. This step-by-step process demonstrates a clear and methodical approach to solving proportions. Understanding these steps and the underlying principles is crucial for mastering this essential mathematical skill. Proportions are a fundamental concept with numerous applications in various fields, making it important to have a solid grasp of how to solve them. The techniques discussed in this article can be applied to a wide range of proportion problems, providing a versatile tool for problem-solving. By following these steps and practicing regularly, anyone can become proficient in solving proportions and confidently tackle similar challenges.