Solving Exponential Equations $7(9^{8x})=5$ With Irrational Solutions

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In the realm of mathematics, exponential equations hold a significant place, often presenting intriguing challenges that require a blend of algebraic manipulation and logarithmic understanding. This article delves into the intricacies of solving exponential equations, with a particular emphasis on expressing irrational solutions in their exact form. We will dissect the equation 7(98x)=57(9^{8x})=5, guiding you through the step-by-step process of isolating the variable and arriving at a precise solution.

Understanding Exponential Equations

Before we embark on solving the specific equation, let's establish a solid foundation by understanding what exponential equations truly are. At their core, these equations feature a variable in the exponent, creating a dynamic relationship where the base is raised to a power that is yet to be determined. The general form of an exponential equation can be represented as ax=ba^x = b, where 'a' is the base, 'x' is the exponent (which contains the variable), and 'b' is the result. Solving these equations involves skillfully unraveling this relationship to pinpoint the value of 'x' that satisfies the equation.

Why are exponential equations important? They are not merely abstract mathematical constructs; they are powerful tools for modeling real-world phenomena. From population growth and radioactive decay to compound interest and the spread of epidemics, exponential equations provide a framework for understanding and predicting change over time. Their applications extend far beyond the classroom, making them essential for scientists, economists, engineers, and countless other professionals.

To successfully solve exponential equations, we often employ the power of logarithms. Logarithms are, in essence, the inverse of exponentiation. The logarithm of a number to a given base is the exponent to which the base must be raised to produce that number. In simpler terms, if ax=ba^x = b, then logab=x\log_a{b} = x. This fundamental relationship allows us to "bring down" the variable from the exponent, making it accessible for algebraic manipulation. Understanding the properties of logarithms, such as the product rule, quotient rule, and power rule, is crucial for navigating the complexities of solving exponential equations.

Solving the Equation 7(98x)=57(9^{8x})=5

Now, let's turn our attention to the specific equation at hand: 7(98x)=57(9^{8x})=5. This equation presents a classic example of an exponential equation that can be solved using logarithms. Our objective is to isolate 'x', the variable nestled within the exponent. To achieve this, we will systematically apply algebraic techniques and logarithmic properties.

Step 1: Isolate the Exponential Term

The first step in solving any equation is to isolate the term containing the variable. In this case, we want to isolate the exponential term, 98x9^{8x}. To do this, we divide both sides of the equation by 7:

7(98x)/7=5/77(9^{8x}) / 7 = 5 / 7

This simplifies to:

98x=5/79^{8x} = 5/7

Now, the exponential term is isolated on one side of the equation, paving the way for the next step.

Step 2: Apply Logarithms

With the exponential term isolated, we can now introduce logarithms to "bring down" the exponent. The key here is to apply the same logarithmic function to both sides of the equation to maintain equality. While we can use any base for the logarithm, the common logarithm (base 10) or the natural logarithm (base 'e') are often preferred due to their availability on calculators.

Let's use the natural logarithm (ln) in this case:

ln(98x)=ln(5/7)ln(9^{8x}) = ln(5/7)

Here's where the power of logarithms truly shines. The power rule of logarithms allows us to move the exponent, 8x, from its position as an exponent to a coefficient:

8xln(9)=ln(5/7)8x * ln(9) = ln(5/7)

This transformation is crucial because it frees the variable 'x' from the exponent, making it accessible for further manipulation.

Step 3: Isolate the Variable

Now that 'x' is no longer trapped in the exponent, we can isolate it using basic algebraic operations. Our goal is to get 'x' by itself on one side of the equation. To do this, we first divide both sides of the equation by ln(9)ln(9):

(8xln(9))/ln(9)=ln(5/7)/ln(9)(8x * ln(9)) / ln(9) = ln(5/7) / ln(9)

This simplifies to:

8x=ln(5/7)/ln(9)8x = ln(5/7) / ln(9)

Next, we divide both sides by 8:

(8x)/8=(ln(5/7)/ln(9))/8(8x) / 8 = (ln(5/7) / ln(9)) / 8

This gives us:

x=ln(5/7)/(8ln(9))x = ln(5/7) / (8 * ln(9))

Step 4: Express in Exact Form

The solution we have obtained, x=ln(5/7)/(8ln(9))x = ln(5/7) / (8 * ln(9)), is the exact form of the solution. It represents the precise value of 'x' that satisfies the original equation, expressed using natural logarithms. This is crucial because if we were to use a calculator to approximate the logarithms, we would introduce rounding errors, leading to an approximate solution rather than the exact solution.

The importance of expressing irrational solutions in exact form cannot be overstated. While decimal approximations may be useful for practical applications, they lack the precision and mathematical elegance of the exact form. The exact form allows us to see the solution in its purest form, revealing the underlying mathematical relationships and avoiding the pitfalls of rounding errors.

Step 5: Simplify the Solution (Optional)

While the solution x=ln(5/7)/(8ln(9))x = ln(5/7) / (8 * ln(9)) is in exact form, we can optionally simplify it further using logarithmic properties. Recall the quotient rule of logarithms, which states that ln(a/b)=ln(a)ln(b)ln(a/b) = ln(a) - ln(b). Applying this rule to the numerator, we get:

x=(ln(5)ln(7))/(8ln(9))x = (ln(5) - ln(7)) / (8 * ln(9))

Furthermore, we can express ln(9)ln(9) as ln(32)ln(3^2), and then use the power rule of logarithms to rewrite it as 2ln(3)2 * ln(3). Substituting this into our equation, we get:

x=(ln(5)ln(7))/(82ln(3))x = (ln(5) - ln(7)) / (8 * 2 * ln(3))

Simplifying the denominator, we have:

x=(ln(5)ln(7))/(16ln(3))x = (ln(5) - ln(7)) / (16 * ln(3))

This is an alternative exact form of the solution, which may be considered more simplified by some.

Key Takeaways

Solving exponential equations, such as 7(98x)=57(9^{8x})=5, involves a systematic approach that leverages the power of logarithms. The key steps include isolating the exponential term, applying logarithms to both sides of the equation, using logarithmic properties to bring down the exponent, isolating the variable, and expressing the solution in exact form. Understanding the properties of logarithms is paramount to successfully navigating these steps.

In summary, remember these key points when solving exponential equations:

  • Isolate the exponential term first.
  • Apply logarithms to both sides of the equation.
  • Use the power rule of logarithms to bring down the exponent.
  • Isolate the variable using algebraic manipulations.
  • Express irrational solutions in exact form to maintain precision.

By mastering these techniques, you will be well-equipped to tackle a wide range of exponential equations and appreciate their significance in various mathematical and real-world contexts.

Conclusion

In this comprehensive guide, we have explored the process of solving the exponential equation 7(98x)=57(9^{8x})=5, emphasizing the importance of expressing irrational solutions in their exact form. By understanding the fundamental principles of exponential equations and the properties of logarithms, you can confidently approach and solve these types of problems. The ability to solve exponential equations is a valuable skill in mathematics and has far-reaching applications in various scientific and engineering disciplines. Remember to practice these techniques to solidify your understanding and enhance your problem-solving abilities. The world of mathematics is filled with fascinating challenges, and mastering exponential equations is a significant step towards unlocking its many secrets.