Point-Slope Form Equation Of A Line With Points (7, Y) And (11, -6) And Slope -3

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In the realm of mathematics, particularly in coordinate geometry, understanding the concept of a line and its various forms of representation is fundamental. One such powerful representation is the point-slope form. This article aims to delve into the intricacies of finding the equation of a line when given two points and the slope, and subsequently expressing it in point-slope form. We will specifically address the problem where a line intersects the points (7, y) and (11, -6), has a slope of -3, and we aim to write the equation of this line in point-slope form using the point (7, y). This exploration will not only solidify your understanding of point-slope form but also enhance your problem-solving skills in linear equations. Let's embark on this mathematical journey together and unlock the secrets of lines and their equations.

Decoding the Point-Slope Form

The point-slope form is a versatile way to represent the equation of a line. It elegantly captures the essence of a line using a single point on the line and its slope. The general form of the point-slope equation is:

y - y₁ = m(x - x₁)

Where:

  • (x₁, y₁) represents a known point on the line.
  • m denotes the slope of the line, indicating its steepness and direction.

This form is particularly useful when you have a point and the slope, as it directly plugs into the equation, making it easy to derive the line's equation. The point-slope form provides a direct and intuitive way to express the relationship between the coordinates of any point on the line and its slope, making it a valuable tool in solving various problems in coordinate geometry. Understanding the components of the point-slope form and their roles in defining the line's characteristics is crucial for effectively using this form.

Calculating the Unknown y-coordinate

Before we can express the equation of the line in point-slope form, we need to determine the value of the unknown y-coordinate in the point (7, y). We are given that the line passes through the points (7, y) and (11, -6), and has a slope of -3. We can utilize the slope formula to find the value of y. The slope formula is:

m = (y₂ - y₁) / (x₂ - x₁)

Where:

  • m is the slope of the line.
  • (x₁, y₁) and (x₂, y₂) are the coordinates of two points on the line.

In our case, we have m = -3, (x₁, y₁) = (7, y), and (x₂, y₂) = (11, -6). Plugging these values into the slope formula, we get:

-3 = (-6 - y) / (11 - 7)

Simplifying the denominator, we have:

-3 = (-6 - y) / 4

To solve for y, we can multiply both sides of the equation by 4:

-12 = -6 - y

Adding 6 to both sides, we get:

-6 = -y

Finally, multiplying both sides by -1, we find:

y = 6

Therefore, the point (7, y) is actually (7, 6). Now that we have the coordinates of one point on the line and the slope, we can proceed to write the equation in point-slope form. This step of calculating the unknown y-coordinate is crucial for accurately representing the line and solving related problems.

Constructing the Point-Slope Equation

Now that we know the slope (m = -3) and a point on the line (7, 6), we can directly substitute these values into the point-slope form equation:

y - y₁ = m(x - x₁)

Plugging in the values, we get:

y - 6 = -3(x - 7)

This is the equation of the line in point-slope form. It elegantly captures the relationship between any point (x, y) on the line and the known point (7, 6), using the slope -3 as the connecting factor. The point-slope form provides a clear and concise representation of the line, making it easy to analyze its behavior and solve related problems. This equation can be further manipulated to obtain other forms of the linear equation, such as slope-intercept form or standard form, depending on the specific requirements or context of the problem. However, in this case, we have successfully constructed the equation in point-slope form as requested.

Alternative Point-Slope Form Using (11, -6)

It's important to note that the point-slope form is not unique; it depends on the point chosen on the line. We used the point (7, 6) to construct the equation, but we could have equally used the point (11, -6). Let's see what the equation looks like if we use this alternative point.

Using the point (11, -6) and the slope m = -3, we substitute these values into the point-slope form equation:

y - y₁ = m(x - x₁)

Plugging in the values, we get:

y - (-6) = -3(x - 11)

Simplifying, we have:

y + 6 = -3(x - 11)

This is another valid point-slope form equation for the same line. Although it looks different from the equation we obtained using the point (7, 6), both equations represent the same line. This highlights the flexibility of the point-slope form and demonstrates that there can be multiple ways to express the equation of a line in this form, depending on the chosen point. This understanding is crucial for recognizing equivalent forms of linear equations and for effectively solving problems where different forms may be encountered.

Converting to Slope-Intercept Form

While we have successfully expressed the equation of the line in point-slope form, it can be beneficial to see how it relates to other forms of linear equations. One common form is the slope-intercept form, which is given by:

y = mx + b

Where:

  • m is the slope of the line.
  • b is the y-intercept (the point where the line crosses the y-axis).

Let's convert the point-slope form equation we obtained using the point (7, 6) to slope-intercept form:

y - 6 = -3(x - 7)

First, distribute the -3 on the right side:

y - 6 = -3x + 21

Next, add 6 to both sides to isolate y:

y = -3x + 27

This is the equation of the line in slope-intercept form. We can see that the slope is -3 (as expected) and the y-intercept is 27. This conversion demonstrates how point-slope form can be easily transformed into other forms, providing a versatile tool for analyzing and representing linear relationships. Understanding the relationships between different forms of linear equations is essential for a comprehensive understanding of linear algebra and its applications.

Applications of Point-Slope Form

The point-slope form is not just a theoretical concept; it has numerous practical applications in various fields. Here are a few examples:

  • Engineering: Engineers often use linear equations to model relationships between physical quantities. Point-slope form can be used to determine the equation of a line representing the stress-strain relationship in a material, given a point on the curve and the slope.
  • Physics: In physics, linear equations are used to describe motion with constant velocity. Point-slope form can be used to find the equation representing the position of an object as a function of time, given its velocity and position at a particular time.
  • Economics: Economists use linear equations to model supply and demand curves. Point-slope form can be used to determine the equation of a demand curve, given the price elasticity of demand and a point on the curve.
  • Computer Graphics: In computer graphics, lines are fundamental building blocks for creating shapes and images. Point-slope form can be used to define lines and perform transformations on them.

These are just a few examples of how point-slope form is used in real-world applications. Its ability to represent a line using a single point and its slope makes it a powerful tool for modeling and solving problems in various disciplines. Understanding the applications of point-slope form enhances its practical value and reinforces its importance in mathematical and scientific contexts.

Conclusion

In this article, we have explored the concept of point-slope form and its application in finding the equation of a line. We successfully determined the unknown y-coordinate, constructed the point-slope equation using two different points, and converted the equation to slope-intercept form. We also discussed the various real-world applications of point-slope form, highlighting its versatility and importance in different fields. The point-slope form is a fundamental concept in coordinate geometry and linear algebra, providing a powerful tool for representing and analyzing linear relationships. Mastering this concept will not only enhance your mathematical skills but also provide you with a valuable tool for solving problems in various scientific and engineering disciplines. As you continue your mathematical journey, remember the power and elegance of the point-slope form and its ability to unlock the secrets of lines and their equations.